2(x+2)^2+13=41

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Solution for 2(x+2)^2+13=41 equation: 



2(x+2)^2+13=41

We move all terms to the left:

2(x+2)^2+13-(41)=0

We add all the numbers together, and all the variables

2(x+2)^2-28=0

We move all terms containing x to the left, all other terms to the right

2(x+2)^2=28

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